What is the x-coordinate of the turning point of y=x2-4x+7
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1. What is the coordinate of the turning point for the equation y=4x2+4x−4?
Answer: (-12 -5)
Rewrite the equation y=4x2+4x−4 in completed square form:
y=(2x+1)2−5
The turning point is where (2x+1)=0 or x = −12
When this is true, y = -5.
2. What is the coordinate of the turning point for the equation y=x2+4x+7?
Answer: (-2, 3)
(x + 2)(x + 2) = x2 + 4x + 4
Therefore (x + 2)2 + 3 = x2 + 4x + 7
Make one of the brackets equal to zero; x = -2. y is equal to the remainder.
Turning point is at (-2, 3).
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