Question

What is the zero of 6x^2 + 7x -3

Answer 1

Answer:

X= 1/3 and -3/2

Step-by-step explanation:

$= 6 {x}^{2} + 7x - 3 \\ = 6 {x}^{2} + 9x - 2x - 3 \\ = 3x(2x + 3) - 1(2x + 3) \\ = (3x - 1)(2x + 3) \\ x = \frac{1}{3} \: \: \: and \: \: \: \frac{ - 3}{2}$

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Answer 2

Answer:

1,-3

Step-by-step explanation:

6x^2+7x-3=0

=>6x^2+9x-2x-3=0

=>2x(x+3)-2(x+3)=0

=>(2x-2)(x+3)=0

One of them has to be 0

Therefore

i)2x=2

x=1

ii)x=-3