Question

What is the zero of 9/4x-4/9?​

Answer 1

Step-by-step explanation:

$\red{1.} \: \: {x}^{2} = 0.01 \\ \\ \implies \: {x}^{2} = \frac{1}{100} \\ \\ \implies \: x = \sqrt{ \frac{1}{100} } \\ \\ \implies \: x = \frac{ \sqrt{1 \times 1} }{ \sqrt{10 \times 10} } \\ \\ \implies \: x = \frac{1}{10} \\ \\ \implies \: x = 0.1 \\ \\ \\ \\ \\ \red{2.} \: \: \frac{9x}{4} - \frac{4}{9} = 0 \\ \\ \implies \: \frac{9x}{4} = \frac{4}{9} \\ \\ \implies \: x = \frac{4 \times 4}{9 \times 9} \\ \\ \implies \: x = \frac{16}{81}$

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