what is the zero of p(x)=(x-1)(x-2)(x-3)
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Answered by
0
Answer:
when x=1 or 2 or 3 then p(x)=0
Answered by
1
Answer:
p(x) = (x - 1)(x - 2)(x - 3) = 0
(x - 1) (x - 2) (x - 3) = 0
=> (x - 1) = 0 and (x - 2) = 0 and (x - 3) = 0
=> x = 1 and x = 2 and x = 3
The zeros are 1, 2 and 3
Ans. 1, 2 and 3
Hope it helps.
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