What is the zeroes of the polynomial p(x)=x^2+x-6 = 0
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Answered by
3
Hlo friends
Here's the answer--------------------------------------------------------
x^2+x-6=0
x^2+3x-2x-6=0
x(x+3)-2(x+3)=0
(x+3)(x-2)=0
x+3=0. x-2=0
x=-3. x=2
Hope my answer will help you
Here's the answer--------------------------------------------------------
x^2+x-6=0
x^2+3x-2x-6=0
x(x+3)-2(x+3)=0
(x+3)(x-2)=0
x+3=0. x-2=0
x=-3. x=2
Hope my answer will help you
Answered by
0
p(x) = x²+x-6 = 0
» x²-2x+3x-6 = 0
» x(x-2) + 3(x-2) = 0
» (x-2) (x+3) = 0
» x-2 = 0 ; x = 2
» x+3 = 0 ; x = -3
Therefore,the zeroes of the given polynomial p(x) are 2 and -3.
» x²-2x+3x-6 = 0
» x(x-2) + 3(x-2) = 0
» (x-2) (x+3) = 0
» x-2 = 0 ; x = 2
» x+3 = 0 ; x = -3
Therefore,the zeroes of the given polynomial p(x) are 2 and -3.
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