what is the zeroes of x
![{x }^{2} - 2x + 8 {x }^{2} - 2x + 8](https://tex.z-dn.net/?f=+%7Bx+%7D%5E%7B2%7D++-+2x+%2B+8)
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Answered by
6
x2-2x+8.
-5.
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Answered by
0
Answer:
there are no real zeroes of this equation.
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