Question

what is the zeroes of
x2 + 7x + 10​

Answer 1

Answer:

x²+7x+10

splitting the middle term

x²+5x+2x+10

x(x+5)+2(x+5)

(x+2)(x+5)

x+2=0

hence x= -2

and

x+5=0

hence x= -5

hence the zeros are -5 and -2

Step-by-step explanation:

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Answer 2

Answer:

-5,-6

Step-by-step explanation:

Let the given polynomial be denoted by f(x).

Then,

f(x)= x2+7x+10

=x2+5x+2x+10 ( by middle term split )

=x (x+5) + 2 (x+5)

=(x+5) (x+2)

Therefore, f (x)= 0

(x+5)(x+2) = 0

x+5=0; x+2=0

x= -5 Or x= -2

Hence the zeros of polynomial are -5,-2