Question

What is the zeros of the following polynomial
x2-√2x-12

Answer 1

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IT'S YOUR ANSWER

x²  - √2x - 12

(Using factorisation method )

x² - 3√2x + 2√2x - 12

x (x - 3√2 ) + 2√2 (x - 3√2)

(x -3√2)(x + 2√2)

The zeros of the equation is

x - 3√2 = 0

x = 3√2

Also, x +2√2 = 0

x  = -2√2

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Answer 2

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The solution is here