Question

What is the zeros p(x) of x2-1

Answer 1

Solution:-

let,

=> x² - 1 = 0

we know formula

a² - b² = (a - b ) (a + b )

so now,

take a 1² which is also 1

=> x² - 1² = 0

(by formula)

=> ( x - 1 ) ( x + 1 ) = 0

=> x - 1 = 0 or x + 1 = 0

=> x = 1 or x = - 1

i hope it helps you.

Answer 2

ok....i will send soon