what is third equation of motion
bobbykapoor:
pls can anyone explain it
Answers
Answered by
1
Third equation of motion is
v²-u²=2as
Proof:-
we know that, v=u+at
v-u=at
t=(v-u)/a
distance=average velocity *time
s=(v+u)/2*(v-u) /a
s=(v+u)(v-u) /2a
s=v²-u²/2a
v²-u²=2as
v²-u²=2as
Proof:-
we know that, v=u+at
v-u=at
t=(v-u)/a
distance=average velocity *time
s=(v+u)/2*(v-u) /a
s=(v+u)(v-u) /2a
s=v²-u²/2a
v²-u²=2as
Answered by
1
Third equation of motion:-
v² = u² + 2as
Here,
v = Final velocity
u = Initial velocity
a = Acceleration
s = Distance
Explanation:-
Average velocity = v + u / 2
Distance = Average velocity * Time
s = (v + u / 2) t
v + u = 2s / t - (i)
We know that,
v = u + at (first equation of motion)
v - u = at - (ii)
Multiply equation (i) & (ii):-
(v + u)(v - u) = 2s / t * at
v² - u² = 2as
v² = u² + 2as Proved.
v² = u² + 2as
Here,
v = Final velocity
u = Initial velocity
a = Acceleration
s = Distance
Explanation:-
Average velocity = v + u / 2
Distance = Average velocity * Time
s = (v + u / 2) t
v + u = 2s / t - (i)
We know that,
v = u + at (first equation of motion)
v - u = at - (ii)
Multiply equation (i) & (ii):-
(v + u)(v - u) = 2s / t * at
v² - u² = 2as
v² = u² + 2as Proved.
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