Question

what is to be repaid on a loan of 20,000 for 1 1/2 years at 10% per annum ​

Answer 1

Answer:

As interest is compounded half yearly, so number of conversion periods in 1

2

1

years is 3, So n=3

rate for half year =

2

1

×10%=5%

A=P(1+

100

R

)

n

A=12000(1+

100

5

)

3

=12000(

100

105

)

3

=Rs.13891.50

Compound interest =A−P

=13891.50−12000

=Rs.1891.50

Answer 2

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what is to be repaid on a loan of 20,000 for 1 1/2 years at 10% per annum .

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$p = 20000$

$r = 10\%$

$(time = 1\frac{1}{2} )$

$t = 3 \: years$

$a = p {(1 + \frac{r}{100}) }^{t}$

$a = 20000 {(1 + \frac{10}{100}) }^{3}$

$a = 20000 ({ \frac{110}{100} )}^{3}$

$a = 20000 {(1.10)}^{3}$

$a = 20000(1.331)$

$a = 26620$

$ci = a - p$

$ci = 26620 - 20000$

$ci = 6620 \: rupees$

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