Question

what is total surface area of frustum​

Answer 1

Answer:

Total surface area of a conical frustum:

A = π * (r12 + r22 + (r1 + r2) * s)

= π * [ r12 + r22 + (r1 + r2) * √((r1 - r2)2 + h2) ]

and

2. A = π l1 (R+r) +πR2 +πr2

Answer 2

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$\bf\Huge\red{\mid{\overline{\underline{ ANSWER }}}\mid }$

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$\Large\fbox{\color{purple}{QUESTION}}$

SURFACE AREA VOLUME FORMULAS

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$\Large\fbox{\color{purple}{ SOLUTION }}$

$\Large\mathcal\green{FRUSTUM}$

$\implies \: tsa = \pi \: l(r1 + r2) + \pi \: {r1}^{2} + \pi {r2}^{2}$

$\implies \: csa = \pi \: l(r1 + r2)$

$\implies volume = \frac{1}{3}\pi \: h( {r1}^{2} + r1.r2 + {r2}^{2} )$

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