Question

What is uniform circular motion? Establish a relationship between linear and angular

velocity​

Answer 1

Answer:

The Physics Classroom Uniform circular motion can be described as the motion of an object in a circle at a constant speed. As an object moves in a circle, it is constantly changing its direction. At all instances, the object is moving tangent to the circle.

Quora Thus, for a given angular velocity ω, the linear velocity v of the particle is directly proportional to the distance of the particle from the centre of the circular path (i.e) for a body in a uniform circular motion, the angular velocity is the same for all points in the body but linear velocity is different for ...

Answer 2

Uniform circular motion can be described as the motion of an object in a circle at a constant speed.

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about an

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves through

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves throughan angle Dq in time Dt sec.

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves throughan angle Dq in time Dt sec.Relation between linear velocity and angular velocity

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves throughan angle Dq in time Dt sec.Relation between linear velocity and angular velocityIf DS is its distance for rotating through angle Dq then,

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves throughan angle Dq in time Dt sec.Relation between linear velocity and angular velocityIf DS is its distance for rotating through angle Dq then, Dq = DS / r

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves throughan angle Dq in time Dt sec.Relation between linear velocity and angular velocityIf DS is its distance for rotating through angle Dq then, Dq = DS / rDividing both sides by Dt, we get Dq / Dt = (DS / r. Dt)

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves throughan angle Dq in time Dt sec.Relation between linear velocity and angular velocityIf DS is its distance for rotating through angle Dq then, Dq = DS / rDividing both sides by Dt, we get Dq / Dt = (DS / r. Dt)r Dq / Dt = DS/Dt

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves throughan angle Dq in time Dt sec.Relation between linear velocity and angular velocityIf DS is its distance for rotating through angle Dq then, Dq = DS / rDividing both sides by Dt, we get Dq / Dt = (DS / r. Dt)r Dq / Dt = DS/DtIf time interval Dt is very small , then the angle through which the particle moves is also very

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves throughan angle Dq in time Dt sec.Relation between linear velocity and angular velocityIf DS is its distance for rotating through angle Dq then, Dq = DS / rDividing both sides by Dt, we get Dq / Dt = (DS / r. Dt)r Dq / Dt = DS/DtIf time interval Dt is very small , then the angle through which the particle moves is also very small and therefore the ratio Dq /Dt gives the instantaneous angular speed wins.

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves throughan angle Dq in time Dt sec.Relation between linear velocity and angular velocityIf DS is its distance for rotating through angle Dq then, Dq = DS / rDividing both sides by Dt, we get Dq / Dt = (DS / r. Dt)r Dq / Dt = DS/DtIf time interval Dt is very small , then the angle through which the particle moves is also very small and therefore the ratio Dq /Dt gives the instantaneous angular speed wins. i.e.

Consider a particle “P” in an object (in XY-plane) moving along a circular paths of radius “r” about anaxis through “O” , perpendicular to plane of the figure i.e. z-axis. Suppose the particles moves throughan angle Dq in time Dt sec.Relation between linear velocity and angular velocityIf DS is its distance for rotating through angle Dq then, Dq = DS / rDividing both sides by Dt, we get Dq / Dt = (DS / r. Dt)r Dq / Dt = DS/DtIf time interval Dt is very small , then the angle through which the particle moves is also very small and therefore the ratio Dq /Dt gives the instantaneous angular speed wins. i.e.V = rw