Question

What is unit vector perpendicular to the plane 2x-3y+4z=5​

Answer 1

Answer:

Let the plane be

(x+y+z−1)+λ(2x+3y+4z−5)=0

⇒(2λ+1)x+(3λ+1)y+(4λ+1)z−(5λ+1)=0

⊥ to the plane x−y+z=0

⇒λ=−

3

1

⇒ the required plane is x−z+2=0