What is
va pour pressure (mm Hg) of
hexane at 2984, when decane has
molar enthalpy
of
va povrization
of
38.9 KJ / mol with normal
341k )
boiling
point of
Answers
Answer:
I plan to use slighty different formulations of the Clausius-Clapeyron Equation in the first several questions. Look to see how they are different. Why do I do this? As you encounter different presentations, you will probably see whatever form of the equation the instructor (or the textbook writer) learned. There is a decent chance that it will be different from the form you learned. I would like for you to see that they are the same equation. As Ludwig Wittgenstein said:
Understanding means seeing that the same thing said different ways is the same thing.
Some brief notes on the units:
1) The natural log term on the left-hand side is unitless. It does not matter what units of pressure you use; the only restriction is that P1 and P2 must be expressed using the same pressure unit.
2) The unit on the temperature term will be K¯1. The unit on R is J mol¯1 K¯1.
3) The K¯1 in the temperature term will cancel with the K¯1 associated with R.
4) This means that the unit on ΔH must be J/mol. This then makes the right-hand side unitless.