what is value k the quadratic equation a2-ka+1=0
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D=b^2-4ac
=k^2-4=0
k= +-2
=k^2-4=0
k= +-2
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a^2-ka+1 is a quadratic equation and if in question it is given that roots of the quadratic equation are equal so we apply quadratic formula in it which is
b^2 - 4ac
Now when we put values we get....
(-k)^2 - 4(1)(1) = 0
k^2 - 4 = 0
k^2 = 4
k = √4
k = 2
b^2 - 4ac
Now when we put values we get....
(-k)^2 - 4(1)(1) = 0
k^2 - 4 = 0
k^2 = 4
k = √4
k = 2
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