Question

what is value of a16 for ap -10 -12 -14​

Answer 1

Answer:

$first \: \: term = - 10\\ \\ common \: \: difference = - 2 \\ \\ = > a_{16} = a + 15d \\ \\ = > a_{16} = - 10 +15( - 2) = - 40$

Answer 2

Answer:

a16= -40

Step-by-step explanation:

a= 10

d= a2-a1

= -12 +(-10)

= -2

n= 16

a16= a+(n-1)d

a16= -10 + (16-1)(-2)

a16= -10 + 15×(-2)

a16= -10 - 30

a16= -40

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