Question

what is value of argument of Z=-6+i​

Answer 1

Answer:

z=x+iy= -6+i

where x= -6 and y=1

$\tan( \alpha ) = \frac{y}{x} = \frac{1}{ - 6} \\ so \: \alpha = { \tan }^{ - 1} ( \frac{ - 1}{6} ) \\ \alpha \: is \: the \: argument \: of \: z$