What is value of cos6theta in terms of cos
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cos6Q=cos2*3Q
=2cos^2Q-1
=2(2(cos^2)Q-1)^2-1
=2(4(cos^2)Q+1-4cosQ)-1
=8(cos^2)Q-8cosQ+7
=2cos^2Q-1
=2(2(cos^2)Q-1)^2-1
=2(4(cos^2)Q+1-4cosQ)-1
=8(cos^2)Q-8cosQ+7
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