Math, asked by swathyswats02, 3 months ago

What is value of f (-3/2) when f (x)= X²-4x+7

Answers

Answered by Anonymous
9

Step-by-step explanation:

If f(x)=x

2

−4x+3

F(2)=2

2

−4(2)+3

=4−8+3

=−4+3

=−1

F(1)=(1)

2

−4+3

=1−4+3−3+3

=0

F(2)−F(1)

=−1+0

=−1

helpful to you

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Answered by Anonymous
3

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The value of f ( \sf\frac{-3}{2} ) is \sf\frac{61}{4}

Step by step explanation:

Given :

The value of f ( \sf\frac{-3}{2} )

When f ( x ) = x² - 4x + 7

Solution :

According to the question the value of x here is given as \sf\frac{-3}{2} ,

To get the solution we should substitute the value of x in the given statement ,

  • f ( x ) = x² - 4x + 7

  • f ( \sf\frac{-3}{2} ) = \sf{\frac{-3}{2}}^2[/Tex] - 4([tex]\sf\frac{-3}{2}) + 7

  • \sf\frac{9}{4} + 6 + 7

  • \sf\frac{9}{4} + 13

  • \sf\frac{9}{4} + \sf\frac{13}{1}

  • Take LCM of 1 and 4 that is 4

  • \sf\frac{9}{4} + \sf\frac{13\:\times\:4}{1\:\times\:4}

  • \sf\frac{9}{4} + \sf\frac{52}{4}

  • \sf\frac{9\:+\:52}{4}

  • \sf\frac{61}{4}
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