Question

what is value of k if if one root of the quadratic equation kx 2 - 7 x + 12 =0is3​

Answer 1

$\huge \star \underline \pink{AnsWeR}$

x= 3

k(3)²-7(3)+12=0

9k-21+12=0

9k-9=0

k=9/9=1

$\huge \star \underline \pink{k = 1}$

Answer 2

Answer:

the value of'k' is 1.

this is your answer for your doubt question.

Step-by-step explanation:

we know that,

'3' is a root of quadratic equations (kx^2-7x+12).

then,we write that

x=3.

putting the value of 'x' in quadratic equations.Then we get the value of'k'.

so,we firstly put it

k×(3)^2-(7×3)+12=0

k×9-21+12=0.

9k-9=0

9k=9

k=9/9

k=1.

So,we get the value of'k'by putting the value of 'x' in equation.

I think it is standard answer and that answers is helpful and satisfying your mind and heart.

when this answer is appreciable , then tag the brainlist and like button,Ok.

thanks u .

I'm your helper.