Math, asked by chouhanbharat1673, 1 year ago

what is value of log(e(e(e....)^1/2)^1/2)^1/2? Base of the log is e
(a)0(b)1/3(c)1/2(d)1

Answers

Answered by adeshrajputtirwa
0

Answer:

Step-by-step explanation:

=1/2loge

=1/2

Answered by Anonymous
3

Step-by-step explanation:

 \sf \: log( \sqrt{e \sqrt{e \sqrt{e \sqrt{e \sqrt{e......} } } } } ) \\

take

 \sf \: y = \sqrt{e \sqrt{e \sqrt{e \sqrt{e \sqrt{e.....} } } } } \\  \\ </p><p>

then

 \sf \: y = \sqrt{ey}</p><p>   \\ </p><p> \sf \: {y}^{2} = e</p><p>

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