what is value of log(e(e(e....)^1/2)^1/2)^1/2? Base of the log is e
(a)0(b)1/3(c)1/2(d)1
Answers
Answered by
0
Answer:
Step-by-step explanation:
=1/2loge
=1/2
Answered by
3
Step-by-step explanation:
take
then
Similar questions