what is value of root of 20+under root of 20+ upto infinite terms
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hey mate
here is your solution.....
we have to assume that this equation is equal to x(or any variable).
thus,
x=√20+(√20+(√20.....∞)
so we have assumed that 20+(√20+(√20.....∞) is x.
so ,
it can be written as
x=√(20+x)
squaring both sides,
x²=20+x
x²-x-20=0
x²-5x+4x-20=0
x(x-5)+4(x-5)=0
(x-5)(x+4)=0
x=5,-4
thus,x=5 (answer)
Anonymous:
welcome
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