Question

What is value of tan A, if sin A= ⅗ and cos A = ⅘

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Answer 1

sin3/5

cos4/5

tan theta =sin theta/cos theta

tan A=3/4

Answer 2

Step-by-step explanation:

$\bold{Given \: that,}$

$\sf \: sin = \frac{3}{5} \\ \sf \: cos = \frac{4}{5}$

we know that,

$\sf \: tan= \frac{opposite}{adjacent} \\ \sf \: \tan = \frac{sin}{cos}$

Now,

$\sf \: tan = \frac{ \frac{3}{5} }{ \frac{4}{5} } \\ \sf \: so \: tan= \frac{3}{4}$

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$\bf \purple{cosine \: and \: tangent \: formulas,}  \\ \sf \: sin= \frac{opposite}{hypotenuse} \\ \\ \sf cos= \frac{adjacent}{hypotenuse} \\ \\ \sf \: tan= \frac{opposite}{adjacent}$