what is values of x,
3x^2+12xy+2y^2
here the value of y = 4x
CAN ANYONE ABLE TO SOLVE IT
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x=1/√83
Step-by-step explanation:
Here, y=4x
3x^2 + 12x(4x) + 2(4x)^2
3x^2 + 48x^2 + 32x^2 = 0
83x^2 = 0
x^2 = 1/83
X = 1/√83
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