Math, asked by jazziyer9, 2 months ago

what is valur of the differntiation of sin(4x)^2 at x=0

Answers

Answered by tbnrtanish
1

Answer:

The answer is 0 Hope it helps

Answered by adarsh6780
0

Answer:

The answer to your solution is 8 sin(4x)^2, putting x as zero , teh naswer woudl be zero.

Step-by-step explanation:

Diffrenciating sin(4x)^2 with respect to x.

Splitting by chain rule it would be

d(Sin(4x))^2/dSin(4x))*dSin(4x)/d(4x)*d(4x)/dx.

8 sin(4x)^2

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