What is velocity acquired by a mass dropped from a height of 100m. (ms2)
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Use conservation of energy
Potential energy at height 100 m = Kinetic energy at ground
mgh = 0.5mv²
Rearrange the above equation
v = √(2gH)
= √(2 × 10 m/s² × 100 m)
= 20√5 m/s
Potential energy at height 100 m = Kinetic energy at ground
mgh = 0.5mv²
Rearrange the above equation
v = √(2gH)
= √(2 × 10 m/s² × 100 m)
= 20√5 m/s
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