what is vertix
of the para bala
bola x² 4ay
is
Answers
Answer:
The given equation of the parabola is x^2 = 4by
For obvious reasons, vertex of any parabola is defined as the point where the slope of the curve becomes zero or changes sign.
Here,
x^2 = 4ay
or,
y= x^2/4a
So,
dy/dx = 2x/4a = x/2a
Clearly, this curve will have its slope zero at x=0
Hence, this parabolic curve will have its vertex as (0,0)
We obtained also the ordinate (y-coordinate) to be zero by putting in x=0 in the equation of the given parabola and hence we obtained the desired answer (0,0)
Step-by-step explanation:
the given parabola x square =6y
x square =4. 3/2 y
compare the above equation with standard form of parabola x square =4ay,we get ,a=3/2
therefore ,the axis of parabola is along positively y-axis and its equations is x=0
the coordinates of vertices are (0,0) and the coordinates of its focus are (0,3/2) the length of its latest rectum =4a=4.3/2=6 units and the equation of its directories is y=-a then y=-3/2 then y + 3/2 =0 then 2y+3=0.
here the x vertix mean where the parabola point crosess its axis of symmetry
I think this information will help u to understand and learn the process
easily