What Is Volume Occupied By 16 G Of Oxygen At Stp?
Answers
Answered by
3
Hi there,
◇ Key
1 mole of gas occupies 22.4L volume at STP
◇ Given
16 gm O2
16g ×( 1mol / 32gm ) × (22.4 L / 1mol ) = 11.2 L
◇ Other way
Number of mols = mass ÷ molar mass
= 16 ÷ 32 = 0.5 mol
1mol = 22.4 L
0.5 mol = 11.2L
♡ Hope the answer is helpful
♡ Plz mark it as brainliest
Similar questions