English, asked by sasankasekhargiri, 8 months ago

What is volume occupied by 1g equivalent of oxyen at NTP. Calculate the number of molecules in it.

Answers

Answered by Zaimakhan177
0

Answer:

At STP, volume of 2g of H  

2

​  

 = 22.4l

∴ volume of 1g of H  

2

​  

 = 11.2l

A) At STP, volume of 32g of oxygen = 22.4l

B) At STP , volume of 28g of nitrogen = 22.4l

∴ volume of 14g of nitrogen = 11.2l

C) At STP, volume of 71g of chlorine =  22.4l

∴ volume of 35.5g of chlorine = 11.2l

D) At STP volume of 4g of helium = 22.4l

Therefore (B) and (C) has same volume as 1g of hydrogen at STP.

Explanation:

Answered by aaradhyadixit216
0

Answer:

The volume of given amount of H2 at NTP is 11.2L.

Explanation:

To calculate the number of moles, we use the equation:

NO. OF MOLES = Given Mass/Molar Mass.

Given mass of hydrogen = 1 gMolar mass of hydrogen = 2 g/mol

Putting values in above equation, we get:

Moles of H2= 1g/2g per mole.

At NTP:

1 mole of a gas occupies 22.4 L of volume.

So, 0.5 moles of hydrogen gas will occupy= 22.4 L/1mol X 0.5 mol=11.2 L of volume.

Hence, the volume of given amount of H2 at NTP is 11.2L.

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