What is volume occupied by 1g equivalent of oxyen at NTP. Calculate the number of molecules in it.
Answers
Answer:
At STP, volume of 2g of H
2
= 22.4l
∴ volume of 1g of H
2
= 11.2l
A) At STP, volume of 32g of oxygen = 22.4l
B) At STP , volume of 28g of nitrogen = 22.4l
∴ volume of 14g of nitrogen = 11.2l
C) At STP, volume of 71g of chlorine = 22.4l
∴ volume of 35.5g of chlorine = 11.2l
D) At STP volume of 4g of helium = 22.4l
Therefore (B) and (C) has same volume as 1g of hydrogen at STP.
Explanation:
Answer:
The volume of given amount of H2 at NTP is 11.2L.
Explanation:
To calculate the number of moles, we use the equation:
NO. OF MOLES = Given Mass/Molar Mass.
Given mass of hydrogen = 1 gMolar mass of hydrogen = 2 g/mol
Putting values in above equation, we get:
Moles of H2= 1g/2g per mole.
At NTP:
1 mole of a gas occupies 22.4 L of volume.
So, 0.5 moles of hydrogen gas will occupy= 22.4 L/1mol X 0.5 mol=11.2 L of volume.
Hence, the volume of given amount of H2 at NTP is 11.2L.