Question

what is volume of 32g of sulferdioxide is measured in s. t p
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Answer 1

Answer:

11.4 L

Explanation:

Given Weight :- 32g

Volume = No of  moles * 22.4 L

No of moles = weight / gram molecular weight (G.M.W)

No of moles = 32/64                              (SO2 = 32 + 16 *2 = 64)

No of moles = 1/2

Volume = 1/2 * 22.4 L

Therefore Volume = 11.4 L