what is volume of 6g hydrogen at 1atm and 273k
Answers
Answered by
2
,.....................
Attachments:
Yusufyuhani:
thanks
Answered by
0
u can use formula PV=nRT
by applying it
p=1atm
r=0.082
t=273k
v=?
n=6
1×v=6×0.082×273
v=6×0.082×273
v=134.316 L
by applying it
p=1atm
r=0.082
t=273k
v=?
n=6
1×v=6×0.082×273
v=6×0.082×273
v=134.316 L
Similar questions