Question

What is weight of calcium hydroxide (Ca(OH),] in 100 ml of 0.01 M solution?
(At Mass of Ca - 40).​

Answer 1

Answer:

0.111

Explanation:

GMW OF CaCL2= 40+71=111

M=W÷GMW×1000÷V

0.01=W÷111×1000÷100

  W=0.01g

Answer 2

The weight of calcium hydroxide $(Ca(OH)_2$ in 100 ml of 0.01 M solution is 0.04 grams.

Explanation:

Molarity : It is defined as the number of moles of solute present in one liter of solution.

Formula used :

$Molarity=\frac{n\times 1000}{V_s}$

where,

Molarity = 0.01 M

n= moles of solute  

$V_s$ = volume of solution in ml = 100 ml

moles of solute =$\frac{\text {given mass}}{\text {molar mass}}=\frac{xg}{40g/mol}$

Now put all the given values in the formula:

$0.01M=\frac{x\times 1000}{40\times 100ml}$

$x=0.04g$

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