What is Williamson's continuous etherification process? Is it a continuous process? Give reasons?
Answers
Answer:
Excess of ethanol is distilled with conc sulphuricacid at 413 K to give diethylether.
2C
2
H
5
−OH
conc.H
2
SO
4
413K
C
2
H
5
−O−C
2
H
5
+H
2
O
Experimental process: Equal volumes of ethanol and conc. sulphuricacid are kept in distillation flask. Ethanol reacts with conc. sulphuricacid to give ethyl:hydrogensulphate. Then excess ethanol is added to distillation flask, which then reacts with ethyl:hydrogensulphate to form diethylether.
The diethylether produced distills over. sulphuricacid is regenerated in second step and is reused in first step. Hence, small amount of sulphuricacid converts large amount of Ethanol into diethylether and the process becomes continuous. Hence, the process is named continuous etherification process.
Answer:
Deprotonated alcohol and an organohalide are combined in the Williamson Ether Synthesis process to create ether. A primary alkyl halide and an alkoxide ion often react in an SN² reaction to produce Williamson ether. Williamson's continuous etherification is an application of Williamson ether synthesis.
Explanation:
Alcohol is used in excess during the Williamson continuous etherification process reaction, and any remaining alcohol is distilled as soon as it forms.
This procedure is referred to as the Williamson continuous etherification since sulfuric acid theoretically stays undiminished in the reaction flask.
The procedure of continuous etherification is used to create diethyl ether.
Yes, it is a continuous process because sulphuric acid is present in excess which initiates the reaction again.
Hence, the explanation for each question is explained above.
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