Physics, asked by Harishkrishna4723, 11 months ago

What is wrong with this downforce calculcation?

Answers

Answered by Sushank2003
3
I tried calculating the downforce of a spoiler I need for a robot. I used this formula.

F=12Acaρv2F=12Acaρv2

Where ρρ is air density, vv is the speed of my robot, caca is the lift coefficient and AA is the windage of the spoiler which I calculate by multiplying its width, length and angle of attack in radians.

A=wlsin(απ180)A=wlsin⁡(απ180)

I used the following values for calculation.

w=0.07m,l=0.04m,α=45∘w=0.07m,l=0.04m,α=45°

ca=1ca=1, because I don't know a better approximation.

ρ=1.2041kgm3ρ=1.2041kgm3

v=3.5msv=3.5ms

And I got as result, that the downforce is around 0,0146 Newton which seems a lot too small. What is wrong with my calculation, or is it actually correct? (I need to compensate about 50N in small turns.)

hope that help you
Answered by Anonymous
0
Hey mate ^_^

Nothing is wrong with down force calculation. See the force produced on the spoiler will be a result of a pressure difference.

A difference of pressure will create a force in a certain certain area of the material and the value is not too far from the true. It is probably pointless to use a spoiler with that size and velocity. 

#Be Brainly❤️
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