# What is x^2 + 2x + 4 = 0?

## Answers

__Given__ **:****-**** **find the nature of the roots of x² + 2x + 4 = 0

__Answer__ **:****-**** **

we know that, If Ax² + Bx + C = 0 ,is any quadratic equation, then its discriminant is given by ,

- D = B² - 4AC .
- If D = 0 , then the given quadratic equation has real and equal roots .
- If D > 0 , then the given quadratic equation has real and distinct roots .
- If D < 0 , then the given quadratic equation has unreal (imaginary) roots .

So, comparing x² + 2x + 4 = 0 with Ax² + Bx + C = 0 we get,

- A = 1
- B = 2
- C = 4

then,

→ D = B² - 4AC

→ D = (2)² - 4*1*4

→ D = 4 - 16

→ D = (-12)

→ (-12) < 0 .

→ **D < 0 .**

therefore, we can conclude that , the given quadratic equation has **unreal (imaginary)** roots .

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JEE mains Question :-

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__SOLUTION__

__SOLUTION__

__TO DETERMINE__

Type of the equation

__CONCEPT____ ____TO BE____ ____IMPLEMENTED__

__Quadratic____ ____Equation__

A quadratic equation is an algebraic equation consisting of variables and constants and equality sign in which the highest power of its variable that appears with nonzero coefficient is two

__General____ ____form____ ____of a____ ____quadratic____ ____equation__

The general quadratic equation is of the form

__EVALUATION__

Here the given equation is

The variable is x

Now the equation is of the form

In the equation the highest power of its variable that appears with nonzero coefficient is two

So the equation is **a**** ****quadratic**** ****equation**** **

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