Question

What is x if ln(3x2)+ln(x4)+ln(7)=0?

Answer 1

$heya \\ \\ ln(6 \times x {}^{4} \times 7 ) = ln(1) \\ \\ becoz \: \: \: \: \: \: ln(m) + ln(n) + ln(p) = ln(m \times n \times p) \\ and \: \: \: \: ln(1) = 0 \\ \\ = > \\ \\ 42 \times x {}^{4} = 1 \\ \\ = > \\ \\ x {}^{4} = 1 \div 42 \\ \\ = > \\ \\ x = (1 \div 42) {}^{1 \div 4}$