Math, asked by jhennzylmyejavier, 1 year ago

What is x in 4x²-m²n⁴=0

Answers

Answered by Anonymous
7

4x² = m²n⁴

x² = m²n⁴/4

x = √m n² / 2

Answered by rijjuramesh2012
0

Answer:

Step-by-step explanation:

4x^2-m^2n^4=0

4x^2=m^2n^4

x^2=1/4(m^2n^4)

x=1/2 (m.n^2)

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