Math, asked by StarTbia, 1 year ago

What is 'x' in the figure.

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Answers

Answered by TooFree
8

∠BOA = 3x + 10 (isosceles triangle)

∠COD = 3x + 10 (Vertically opposite angles)

∠CDO = 3x + 10 (isosceles triangle)

-

(3x + 10) + (3x + 10) + 2x = 180 (sum of triangles)

-

Solve x:

(3x + 10) + (3x + 10) + 2x = 180

3x + 10 + 3x + 10 + 2x = 180

8x + 20 = 180

8x = 160

x = 20

-

Answer: x = 20

Answered by sonabrainly
3

∠BOA = 3x + 10 (isosceles triangle)

∠COD = 3x + 10 (Vertically opposite angles)

∠CDO = 3x + 10 (isosceles triangle)

-

(3x + 10) + (3x + 10) + 2x = 180 (sum of triangles)

-

Solve x:

(3x + 10) + (3x + 10) + 2x = 180

3x + 10 + 3x + 10 + 2x = 180

8x + 20 = 180

8x = 160

x = 20

-

answer is 20

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