Question

What is (x2-7x + 10) divide (x-5) what is the answer of this problem

Answer 1

$\frac{x^{2} - 7x + 10 }{(x-5)} \\= \frac{x^{2} - 2x - 5x + 10 }{(x-5)} \\=\frac{x(x- 2)-5(x-2) }{(x-5)} \\=\frac{(x-2)\cancel {(x-5)}}{\cancel {(x-5)}} \\=(x-2)$

Therefore.,

$\red{\frac{x^{2} - 7x + 10 }{(x-5)}}\green { = (x-2)}$

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