What is your answer: 1/a+1/b=1/a+b, Help me, a=?, b=?
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1/a + 1/b = 1/(a+b)
(a+b) / ab = 1/(a+b)
(a+b)² = ab
a² + b² + 2 ab = ab
a² + b² = - a b
We know that always a² + b² >= 2 a b
as (a-b)² >= 0
but - a b < 2 a
b
Hence there is no solution to the given problem.
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Another way:
a² + b² = - ab
As LHS is always positive, a*b is negative. Let us assume that b is
negative.
let b = - c , where c is positive. and a
is positive.
So a² + c² = a c
a² + c² - 2 a c = - a c
(a - c)² = - a c
This is not possible. There is no solution to the given problem. There
are no real a , b such that 1/a + 1/b = 1/(a+b).
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