Question

what is your ecq experience?
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Answer 1

Answer:

Solution



Verified by Toppr

x=5t2+18t(1)v=dtdx=10t+18

att=2s,v=10×2+18=38m/s

(2)Average,velocity=timedisplacementatt=2,x=5(2)2+18×2=56mt=3,x=5(3)2+18×3=99mAveragevelocity=3−299−56=43 m/s