Question

What is Z in the following sequence of reactions?
z with Pcl5 givesX, X with alc KOH gives Y , y with - conc h2SO4 and h2o boiling gives back Z

(1) CH3CH2CH2OH
(3) (CH3CH2)2CHOH
(2) CH3CHOHCH3
(4) CH3-CH=CH2​

Answer 1

Z is 2-Propanol ( CH$_{3}$CHOHCH$_{3}$ ) .

• When CH$_{3}$CHOHCH$_{3}$ is reacted with PCl$_{5}$ , 2-Chloropropane ( CH$_{3}$CHClCH$_{3}$ ) is formed . Thus , X is 2-Chloropropane ( CH$_{3}$CHClCH$_{3}$ ) .

• When CH$_{3}$CHClCH$_{3}$ is reacted with alc. KOH , Propene ( CH$_{3}$-CH=CH$_{2}$​ ) is formed . Thus , Y is CH$_{3}$-CH=CH$_{2}$​ .

• When CH$_{3}$-CH=CH$_{2}$​ is treated with conc. H$_{2}$​SO$_{4}$ and H$_{2}$​​O , 2-Propanol ( CH$_{3}$CHOHCH$_{3}$ ) is formed .

• The molar mass of 2-Propanol ( CH$_{3}$CHOHCH$_{3}$ ) is 60.1 g/mol .