Question

What isAngle between A=5i-5j and B=5i-5j?

Answer 1

Answer:

Angle, $\theta=0^{\circ}$

Explanation:

It is given that,

Vector A, $A=5i-5j$

Vector B, $B=5i-5j$

Magnitude of vector A, $|A|=\sqrt{5^2+(-5)^2} =7.07$

Magnitude of vector B, $|B|=\sqrt{5^2+(-5)^2} =7.07$

Let $\theta$ is the angle between A and B. It can be calculated using the formula of dot product as :

$A.B=|A||B|\ cos\theta$

$cos\theta=\dfrac{A.B}{|A||B|}$

$cos\theta=\dfrac{(5i-5j).(5i-5j)}{7.07\times 7.07}$

$cos\theta=\dfrac{25+25}{(7.07)^2}$

$\theta=0^{\circ}$

So, the angle between two vectors is 0 degrees. Hence, this is the required solution.

Answer 2

Explanation:

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