What kinetic energy of an object mass m moving with velocity of 5m/s is 25j. What will be it's kinetic energy when it's velocity is doubled?
Answers
Answer:
100 J
Explanation:
If the velocity of an object is doubled, then its kinetic energy becomes 4 times the original value, because it is proportional to the square of the velocity. Hence, kinetic energy = 25 × 4 = 100 J.
Answer:
Kineticenergy,E
k
= \sf\frac{1}{2}mv^2
2
1
mv
2
\sf{i.e.}i.e. \sf{E_k}E
k
\propto∝ {mv^2}mv
2
___________________________
\bold{\large{\boxed{\sf{\green{Given:}}}}}
Given:
\sf{E_k1}E
k
1 \sf{=25J\:and\:V_1=5m/s}=25JandV
1
=5m/s
\bold{\large{\boxed{\sf{\red{If\:velocity\:is\:doubled:}}}}}
Ifvelocityisdoubled:
\sf{i.e.\:V_2=2V_1}i.e.V
2
=2V
1
\sf{K.E,\:E_k2}K.E,E
k
2 \propto∝ \sf{(V_2)^2)\:or\:E_k2}(V
2
)
2
)orE
k
2 \propto∝ \sf{(2V_1)^2\:or\:E_k}(2V
1
)
2
orE
k
\propto∝ \sf{4V_1^2}4V
1
2
_________________________________
\sf\underline{Thus,}
Thus,
\sf\frac{E_k1}{E_k2}
E
k
2
E
k
1
=\sf\frac{25}{E_k2}
E
k
2
25
=\sf\frac{V_1^2}{4V_1^2}
4V
1
2
V
1
2
\sf{E_k2=25\times4=100J}E
k
2=25×4=100J
_________________________________
Similarly if velocity becomes three times, K.E becomes (3)² times or 9 times.
i.e. \sf{25J\times9=225J}25J×9=225J
Explanation:
hope it's will help u