Math, asked by iqbalkhehra, 1 year ago

what ks the value of (cos²67°-sin²23°)?

Answers

Answered by ravhi24
0
cos²67 - sin ²(90-67)
= cos²67 -cos²67
0
Answered by Anonymous
0

cos^2 67° - sin^2 23° = cos^2 67° - {sin 23°}^2




= cos^2 67° - {sin(90 - 67)°}^2





= cos^2 67 - {sin(90 - 67)°}^2    .....   [sin(90 - Ф) = cos Ф]




= cos^2 67° - cos^2 67°




= 0




cos^2 67° - sin^2 23° = 0

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