What least no x must be subtract from 797 so that (797-x) on being divided by 8, 9, 11 leaves in each case the same remainder 4?
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LCM(8, 9, 11) = 792
In order to leave a Remainder of 4 when divided by 8, 9, 11, then we need to add 4 to the LCM(8, 9, 11) = 4 + 792 = 796
So we require number 796 so that it leaves a Remainder 4 when divided by 8, 9 & 11.
We need to subtract “1” from 797 to be able to divide by 8, 9, 11 leaving a Remainder 4.
Answer: 1
In order to leave a Remainder of 4 when divided by 8, 9, 11, then we need to add 4 to the LCM(8, 9, 11) = 4 + 792 = 796
So we require number 796 so that it leaves a Remainder 4 when divided by 8, 9 & 11.
We need to subtract “1” from 797 to be able to divide by 8, 9, 11 leaving a Remainder 4.
Answer: 1
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Answer:
LCM(8, 9, 11) = 792
In order to leave a Remainder of 4 when divided by 8, 9, 11, then we need to add 4 to the LCM(8, 9, 11) = 4 + 792 = 796
So we require number 796 so that it leaves a Reminder 4 when divided by 8, 9 & 11.
We need to subtract “1” from 797 to be able to divide by 8, 9, 11 leaving a Remainder 4.
Step-by-step explanation:
n order to leave a Reminder of 4 when divided by 8, 9, 11, then we need to add 4 to the LCM(8, 9, 11) = 4 + 792 = 796
So we require number 796 so that it leaves a Reminder 4 when divided by 8, 9 & 11.
We need to subtract “1” from 797 to be able to divide by 8, 9, 11 leaving a Remainder 4.
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