Math, asked by srijita7177, 24 days ago

What least number is divisible by 18, 21, 24 and 30 leaves a remainder 9 ?​

Answers

Answered by HARISHRAGAV
3

2529

Step-by-step explanation:

first of all find LCM of 18 21 24 30

18 = 2x3x3

24=2×2×2×3

21=3×7

30=2×3×5

LCM=2x2x3x3x5x7=2520

NOW Add 9 in LCM which is 2520+9=2529

Now

2529 18-leaving remainder 9 and quotient 13

2529-21-leaving remainder 9 and quotient 12

2529-24-leaving remainder 9 and quotient 105

2529-30-leaving remainder 9 and quotient 84

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Answered by velpulaaneesh123
2

Answer:

2884

Step-by-step explanation:

What is the least number which when divided by 12, 16, 18 and 30 leaves a remainder of 4 in each case but is completely divisible by 7?

First of all find LCM and as it leaves remainder of 4 then the number is LCM +4

12=2×2×3=2^2×3

16=2×2×2×2=2^4

18=2×3×3=3^2×2

30=2×3×5

LCM (12,16,18,30)=2^4×3^2×5

LCM=16×9×5

LCM=720

The number can be 720+4=724

But the condition is, the number should also be completely divisible by 7

As 724 is not completely divisible by 7

Therefore the number is multiple of 720 plus 4 which is divisible by 7

720×2+4=1444 not divisible by 7

720×3+4=2164 not divisible by 7

720×4+4=2884

2884 is completely divisible by 7

Answer is 2884

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