Question

What least number must be added to 1056 so that the sum is comletey divusible by 23?

Answer 1

Hi mate.....
Hope you will like the answer

When we divide 1056 is divided by 23 we get remainder 21

23)1056(045
-92
136
-115
21

So when we divide the number we get remainder 21
So 23-21=2
So we can add 2 so that number is completely divisible by 23
To add 2 in 1056 we get 1058

23)1058(046
-92
138
-138
000
So the new number is 1058 when divided by 23 leaves remainder 0 and quotient 046