Question

What least number must be added to 1056 to get a number exactly divisible by 23? with explanation​

Answer 1

Step-by-step explanation:

⇒ When 1056÷23, we get 21 as a remainder. ⇒ So, 23−21=2 must be added to 1056 in order to sum completely divisible by 23. ∴ The least number should be added to 1056, so that the sum is completely divisible by 23 is 2.

Answer 2

Answer:

When 1056÷23, we get 21 as a remainder.

⇒  So, 23−21=2 must be added to 1056 in order to sum completely divisible by 23.

∴    1056+2=1058

∴    The least number should be added to 1056, so that the sum is completely divisible by 23 is 2.